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lesantik [10]
3 years ago
11

Find the equation of the line that passes through points A and B. y X A (4, 7) B (2, 3)

Mathematics
2 answers:
alexgriva [62]3 years ago
6 0

Answer:

y - 3 = 2(x - 2)

Step-by-step explanation:

As we move from Point B (2, 3) to Point A (4, 7), we see x increasing by 2 from 2 to 4 and y increasing by 4 from 3 to 7.  Hence the rise is 4 and the run is 2, which means that the slope of this line is m = rise / run = 4/2 = 2.

Using the point-slope formula y - k = m(x - h) and the point (2, 3), we get:

y - 3 = 2(x - 2)

g100num [7]3 years ago
3 0

Answer:

y = 2x - 1.

Step-by-step explanation:

The slope = (7-3)/(4-2)

= 4/2

= 2.

y - y1 = m(x - x1)

Here m = 2 , x1 = 2 and y1 = 3. So we have:

y - 3 = 2(x - 2)

y = 2x - 4 + 3

y = 2x - 1.

We have used the point (2, 3) to find the equation but we could have used (4, 7). We would have got the same answer.

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Dafna1 [17]
Pretty sure it is B?
7 0
3 years ago
A rectangular area is to be enclosed by a wall on one side and fencing on the other three sides. If 18 meters of fencing are use
Rashid [163]

Answer:

A = L W= 9*\frac{9}{2}=\frac{81}{2} m^2

Step-by-step explanation:

For this case we assume that the total perimeter is 18 ft, we have a wall and the two sides perpendicular to the wall measure x units each one so then the side above measure P-2x= 18-2x.

And we are interested about the maximum area.

For this case since we have a recatangular area we know that the area is given by:

A= LW

Where L is the length and W the width, if we replace from the values on the figure we got:

A(x)= x *(18-2x) = 18x -2x^2

And as we can see we have a quadratic function for the area, in order to maximize this function we can use derivates.

If we find the first derivate respect to x we got:

\frac{dA}{dx} = 18-4x=0

We set this equal to 0 in order to find the critical points and for this case we got:

18-4x=0

And if we solve for x we got:

x=\frac{18}{4}=\frac{9}{2} m

We can calculate the second derivate for A(x) and we got:

\frac{d^2 A}{dx^2}= -4

And since the second derivate is negative then the value for x would represent a maximum.

Then since we have the value for x we can solve for the other side like this:

L= 18-2x = 18-2 \frac{9}{2}= 18-9 =9m

And then since we have the two values we can find the maximum area like this:

A = L W= 9*\frac{9}{2}=\frac{81}{2} m^2

8 0
3 years ago
Please answer this these are all the points i got left XD
Kazeer [188]
Answer is choice B

The ratio of the sides (first to the second) is 11/9 since we divide 22/18 and reduce that fraction

Once we know the scale factor is 11/9, we square it to get (11/9)^2 = 121/81 which is the ratio of the first area to the second area
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Kisachek [45]

Answer:

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Step-by-step explanation:

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3 years ago
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Rufina [12.5K]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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