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Naily [24]
3 years ago
13

Graphing round each value

Mathematics
1 answer:
Molodets [167]3 years ago
6 0

hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

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The value of k so that the sequence k-1, k+3, 3k-1 forms an arithmetic progression is?​
VashaNatasha [74]

Answer:

k = 4.

Step-by-step explanation:

An arithmetic sequence has a common difference.

So for this to be arithmetic:

k + 3 - (k - 1) = 3k - 1 - (k + 3)

k + 3 - k + 1 = 3k - 1 - k - 3

3 + 1 = 2k - 4

4 + 4 = 2k

k = 4.

The sequence is  3, 7, 11.

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4 years ago
A cell phone company sold 4,000 cell phones in the month of November. In December, the company held its annual sale and sold 22%
makvit [3.9K]
First, move the decimal place from the 22%  so it would be .22 multiply that by 4,000 that would be 880 add that to 4,000 so 4,880 50% of that would be .50x4880= 2440 subtract that from 4,880 so 4,880-2,440=2,440

In November they sold 4,000
In December they sold 4,880
In January they sold 2,440

add these together and in the 3 months the company sold 11,320 cell phones. :)

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3 years ago
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anyanavicka [17]

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