Hello!

We can go through the choices and see if they are true

Choice 1
A function has one output for every input

This is not a function because it has -1 as an output for both 4 and -1

This is the answer
------------------------------------------------------------------------------------------------------
Choice 2
The inputs are the x's

We see that the inputs are -1, 0, 3, and 4

This is true
------------------------------------------------------------------------------------------------------
Choice 3
The outputs are the y's

We see the outputs are -2, -1, and 1

This is true
------------------------------------------------------------------------------------------------------
Choice 4
We can follow the lines and see the relations are

(-1, 1), (0, -2), (3, 1), (4, -1)

This is also true
------------------------------------------------------------------------------------------------------
The only one that was false was the first choice so that is the answer

The answer is A) The diagram represents a function
------------------------------------------------------------------------------------------------------
Hope this helps!

4 0

3 years ago

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

6 0

3 years ago