Answer:
164.2°
Explanation:
speed of wind (w) = 45 km/h due south
speed of aircraft (a) = 165 km/h
in what direction (in degrees) should the aircraft head in so as to fly due west?
To get the direction the pilot should fly, we can form a triangle with the data available where
- the direction of the wind (due south) serves as the opposite side
- the direction the pilot would have to fly so he can end up at he west serves as the hypothenuse
- θ is the angle between the direction the pilot would have to fly and the direction the pilot wishes to fly.
- the direction the pilot wishes to fly ( west) will serve as the adjacent side
- all this can be seen from the attached diagram.
now sin θ =
sin θ =
θ = 0.2728
θ = 15.8°
since we are to use the counter-clockwise from east convention our measurement would have to be taken anticlockwise from the east direction, therefore the direction of the aircraft (Ф) = 180-15.8 = 164.2°
