Answer:
A.2.95 m
B.7
Explanation:
We are given that
Diffraction grating=600 lines/mm
d=
Wavelength of light,
l=4.6 m
A.We have to find the distance between the two m=1 bright fringes

For first bright fringe, =1


The distance between two m=1 fringes

Hence, the distance between two m=1 fringes=2.95 m
B.For maximum number of fringes,


Substitute the values


Maximum number of bright fringes on the scree=
Answer: 53.09Hz
Explanation:
The fundamental frequency of an ideal taut string is:
Fn= n/2L(√T/μ)
Where:
F= frequency per second (Hz)
T= Tension of the string (cm/s sqr)
L= Length of the string (cm)
μ= Linear density or mass per unit length of the string in cm/gm
√T/μ= square root of T divided by μ
It is important to note:
Note: Typically, tension would be in newtons, length in meters and linear density in kg/m, but those units are inconvenient for calculations with strings. Here, the smaller units are used.
F1= 1/2(376cm)(0.01/1) × (√574/(0.036g/cm)(0.1kg/m÷1g/cm)
F1= 0.1329 × 399.30
= 53.09Hz
Answer:
Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field. Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.
Yes, eg., when 2 bodies move in opposite directions
, the relative velocity of each is greater than the individual velocity of either