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never [62]
3 years ago
11

The net external force on the propeller of a 0.75 kg model airplane is 17N forward. What is the

Physics
1 answer:
V125BC [204]3 years ago
8 0

Answer:

23 m/s

Explanation:

The net external force on the propeller is 17N

The airplane is 0.75 kg

Therefore the acceleration of the plane can be calculated as follows

= 17/0.75

= 23 m/s

Hence the acceleration of the airplane is 23 m/s

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A uniform shelf 1.8 meters long with mass 15 kg is mounted by a small hinge on a wall. The beam is held in a horizontal position
jeka57 [31]

Answer:

 T = 153.72 N

Explanation:

For this exercise we must use the conditions of translational and rotational equilibrium.

Let's set a frame of reference on the hinge, start by writing the rotational equilibrium relationship, suppose counterclockwise rotation is positive

We look for the components of the cable tension with trigonometry

           cos 37 = Tₓ / T

           sin 37 = T_{y} / T

           Tₓ = T cos 37

           T_{y} = T sin 37

the expression for rotational equilibrium is

        T_{y} L + Tₓ 0 - W L / 2 - W_light  0.55 = 0

where L is the length L=  1.8 m,

        T_{y} = (W L/2 + W_lght 0.55) / L

        T sin 37 = Mg /2 + m_light g 0.55 / L

        T = (M / 2 + m_light 0.55 / L) g / sin 35

 let's calculate

        T = (15/2 + 4.9 0.55 / 1.8) 9.8 / sin 35

         T = 153.72 N

8 0
3 years ago
Un chico de 45 kg de masa se encuentra de pie sobre la nieve. Calcula la presión sobre este:
vagabundo [1.1K]
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6 0
2 years ago
calculate speed and velocity of the following. the race car was moving for 3.7 hours and during that time it traveled a distance
Ksju [112]

Answer:

v = 135.13 mph

Explanation:

Given that,

The race car was moving for 3.7 hours and during that time it traveled a distance of 500 miles south.

We need to find the speed of the car.

We know that,

Speed = distance/time

So,

v=\dfrac{500\ miles}{3.7\ h}\\\\v=135.13\ mph

So, the speed of the car is equal to 135.13 mph.

7 0
2 years ago
Which statement(s) accurately describe the conditions immediately before and after the firecracker explodes:
lidiya [134]

Answer:

Option C, The total momentum of the fragments is equal to the original momentum of the firecracker.

Explanation:

Kinetic energy of cracker cannot remain constant before and after explosion. It is so because in the process of burning and bursting some amount of kinetic energy is lost in the form of light and heat energy. While the total mass before and after the explosion remains constant due to which the momentum is conserved before and after the explosion

Hence, option C is correct

8 0
3 years ago
Which of the following actions would decrease the energy stored in a parallel plate capacitor when a constant potential differen
Debora [2.8K]

Answer:

increasing the separation between the plates

Explanation:

The increase in the vacuum/separation between the plates in a parallel plate capacitor connected to a constant potential difference decreases the energy stored in the capacitor. the increase in the separation of the plates of a parallel plate capacitor reduces the capacitance of the capacitor because

Q(charge) = CV  V = VOLTAGE , c = capacitance  

E = 1/2 eAV^2/ D  ( ENERGY STORED )

where D = distance between plates, e = dielectric, A = area of capacitor , V = potential difference

6 0
3 years ago
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