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aleksklad [387]
3 years ago
8

Your friend turns the volume up on their speaker system, so that the sound intensity is 4 times greater than it was beforehand.

By what factor has the energy output of the speaker system increased?
Physics
1 answer:
erica [24]3 years ago
4 0

Answer:

4

Explanation:

We know that intensity I = P/A where P = power and A = area through which the power passes through.

Now, let the initial intensity of the speaker be I₀ and its initial power be P₀. Since the intensity is increased by a factor of 4, the new intensity be I and new power be P.

So, I = P/A and I₀ = P₀/A

Now, if I = 4I₀,

P/A = 4P₀/A

P = 4P₀

Now, energy E = Pt, where t = time. So, P = E/t and P₀ = E₀/t

Substituting P and P₀ into the equation, we have

P = 4P₀

E/t = 4E₀/t

E = 4E₀

Since the energy is four times the initial energy, the energy output increases by a factor of 4.

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Two soccer players start from rest, 36 m apart. They run directly toward each other, both players accelerating. The first player
Cerrena [4.2K]
A) Both players are moving by uniformly accelerated motion, and we can write the position at time t of each of the two players as follows:
x_1(t)= \frac{1}{2}a_1 t^2
x_2(t)=d- \frac{1}{2}a_2 t^2
where
a_1 = 0.58 m/s^2 is the acceleration of the first player
a_2=0.42 m/s^2 is the acceleration of the second player
d=36 m is the initial distance between the two players
and where I put a negative sign in front of the acceleration of the second player, since he's moving in the opposite direction of the first player.

The time t at which the two players collide is the time t at which x_1 = x_2, therefore:
\frac{1}{2}a_1 t^2 = d- \frac{1}{2}a_2 t^2
from whic we find
t= \sqrt{ \frac{2d}{a_1+a_2} }= \sqrt{ \frac{2 \cdot 36 m}{0.58 m/s^2+0.42 m/s^2} }=8.5 s

b) We can use the equation of x_1(t) to find how far the first player run in t=8.5 s:
x_1(t)= \frac{1}{2}a_1 t^2= \frac{1}{2}(0.58 m/s^2)(8.5 s)^2=21.0 m
8 0
3 years ago
Compare the gravitational force the sun exerts on Earth to the gravitational force Earth exerts on the sun.
podryga [215]

Answer:

as

  • Mass of sun > Mass of earth

Therefore, the sun will exert more gravitational force on earth.

Explanation:

While comparing the gravitational force exerted by two objects, we need to observe which object has a greater mass.

  • The object with the greater mass exerts a more gravitational force on the other object.

We know that mass of the sun is about 1.99 x 10³⁰ kg, and the earth's mass is only 6.0 x 10²⁴.

as

  • Mass of sun > Mass of earth

Therefore, the sun will exert more gravitational force on earth.

7 0
3 years ago
How much work is done if a 50N weight is lifted to a height of 10m? ​
borishaifa [10]

500J  

Explanation:

Given parameters:

Weight of the body = 50N

Height = 10m

Unknown:

Work done = ?

Solution;

Work done is the force that moves a body through a particular distance in the direction of the force.

In this problem, we can solve the problem by relating work done to the potential energy used in lifting the mass.

  The weight on a body, a force in the presence of gravity

         weight(weight) = mg

  where m = mass of body

              g = acceleration due to gravity

  Work done = Fxd

   Where F = force on the body

               d = distance moved

Potential energy = mgh

    where h is the height

     P.E = work done =  Weight x height = 50 x 10 = 500J  

Learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

6 0
3 years ago
A machine is supplied Energy at a rate of 4000 W and does useful work at a rate of 3760 W. What is the efficiency of the machine
ICE Princess25 [194]
The efficiency of a machine is the ratio between the output power and the power in input:
\epsilon =  \frac{P_{out}}{P_{in}}
in our problem, the output power is 3760 W while the input power is 4000 W, so the efficiency is
\epsilon =  \frac{3760 W}{4000 W} =0.94
So the efficiency of the machine is 94%.
6 0
3 years ago
Read 2 more answers
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Y_Kistochka [10]

Answer:

Answer 11

Explanation:

. Newton's law of gravitation, statement that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them

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3 years ago
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