What is the equation of the circle? Also no links please

Graded Assignment Unit Test, Part 2: More Math Models Answer the questions. When you have finished, submit this assignment to yo

Black_prince [1.1K]

Answer:

Y(n) = 400(2.5)^n

Y = 3,814,697 rice weevils

16.1 weeks

Step-by-step explanation:

To predict the population of rice weevil for any week after the start of the study ; wwe use an exponential function for this purpose :

y(n) = A(1 + r)^n

Where;

Y(n) = population at week n

r = growth rate ; n = number of weeks

A = initial population at the start of the study

r = 150% = 1.5

Hence, we have the equation :

Y(n) = 400(1 + 1.5)^n

Y(n) = 400(2.5)^n

B.)

Population after 10 weeks

n = 10

Y(10) = 400(2.5)^10

Y = 400 * 9536.7431640625

Y = 3814697.265625

Y = 3,814,697 rice weevils

C)

When population will reach 1,000,000,000

We have :

1,000,000,000 = 400(2.5)^n

1000000000 / 400 = 2.5^n

2500000 = 2.5^n

Take the log of both sides :

log(2500000) = nlog(2.5)

6.3979400 = n * 0.3979400

n = 6.3979400 / 0.3979400

n = 16.077649

n = 16.1 weeks approximately

5 0

2 years ago

Find the product of the following polynomials:

qaws [65]

Answer:

A) -84x^3 - 8x

B) -91x^4 + 143x^2 - 65x

C) 12b^2 - 7b - 10.

D) 16x^2 - 72x + 81

Step-by-step explanation:

A) -4x(21x^2-3x+2)

B) -13x(7x^3-11x+5)

C) (3b+2)(4b-5)

D) (4x-9)^2

In A) -4x(21x^2-3x+2) we are multiplying the binomial (21x^2-3x+2) by the monomial -4x; there are two multiplications involved:

-4x(21x^2) = -84x^3

and

-4x(-3x+2) = +12x^2 - 8x.

Hence A) -4x(21x^2-3x+2) = -84x^3 - 8x

B) The work done to find the product in B) is similar: Multiply each term in 7x^3-11x+5 by -13x:

The end result is -91x^4 + 143x^2 - 65x

C) Here we are multiplying together two binomials; we use the FOIL method: Multiply together the First terms, then the Outer terms, then the Inner terms, and finally the Last terms. This results in:

(3b+2)(4b-5) = 12b^2 -15b + 8b -10, or, after simplification, 12b^2 - 7b - 10.

In D) we are squaring a binomial. The formula for this is:

(a - b)^2 = a^2 - 2ab + b^2. Here,

(4x - 9)^2 = 16x^2 - 2(36x) + 81, or 16x^2 - 72x + 81

5 0

3 years ago

The unit cost, in dollars, to produce bins of cat food is $3 and the fixed cost is $6972. The price-demand function, in dollars

stellarik [79]

Answer:

Revenue , Cost and Profit Function

Step-by-step explanation:

Here we are given the Price/Demand Function as

P(x) = 253-2x

which means when the demand of Cat food is x units , the price will be fixed as 253-2x per unit.

Now let us revenue generated from this demand i.e. x units

Revenue = Demand * Price per unit

R(x) = x * (253-2x)

= $253x-2x^2$

Now let us Evaluate the Cost Function

Cost = Variable cost + Fixed Cost

Variable cost = cost per unit * number of units

= 3*x

= 3x

Fixed Cost = 6972 as given in the problem.

Hence

Cost Function C(x) = 3x+6972

Let us now find the Profit Function

Profit = Revenue - Cost

P(x) = R(x) - C(x)

= $253x-2x^2 - (3x + 6972)$

= $253x-3x-2x^2-6972\\= 250x-2x^2-6972\\=-2x^2+250x-6972\\$

Now we have to find the quantity at which we attain break even point.

We know that at break even point

Profit = 0

Hence P(x) = 0

$-2x^2+250x-6972=0\\$

now we have to solve the above equation for x

Dividing both sides by -2 we get

$x^2-125x+3486=0$

Now we have to find the factors of 3486 whose sum is 125. Which comes out to be 42 and 83

Hence we now solve the above quadratic equation using splitting the middle term method .

Hence

$x^2-42x-83x+3486=0\\x(x-42)-83(x-42)=0\\(x-42)(x-83)=0\\$

Either (x-42) = 0 or (x-83) = 0 therefore

if x-42= 0 ; x=42

if x-83=0 ; x=83

Smallest of which is 42. Hence the number of units at which it attains the break even point is 42.

5 0

3 years ago

A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The p

Ksju [112]

Complete question :

A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The population would grow by 30 percent per year

how many after one year

how many after two years

Answer:

39 deers

51 deers

Step-by-step explanation:

The question can be expressed using the compounding rate formula:

A = P(1+r)^t

A = final population ; P = initial population ; rate, r = 30% = 0.3 ; t = time

After 1 year, t = 1

A = 30(1 + 0.3)^1

A = 30(1.3)^1

A = 39 deers

B.)

After 1 year, t = 2

A = 30(1 + 0.3)^2

A = 30(1.3)^2

A = 50.7

A = 51 deers approximately

4 0

2 years ago

A:b= 7:1 Circle the correct equation. a= 7b b=7a a=6b b= 6a

astraxan [27]

Answer:

a= 7b

Step-by-step explanation:

a=7

b=1

a->7=7b(1)

a=7(1)

a=7

7=7

8 0

2 years ago