1
P(V|A) is not 0.95. It is opposite:
P(A|V)=0.95
From the text we can also conclude, that
P(A|∼V)=0.1
P(B|V)=0.9
P(B|∼V)=0.05
P(V)=0.01
P(∼V)=0.99
What you need to calculate and compare is P(V|A) and P(V|B)
P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)
P(V∩A) means, that Joe has a virus and it is detected, so
P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095
P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:
P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085
10k^4+10k^3+8k^2+8k+10/k+1 not sure if this is what you are looking for or not hope it helps
65 % ------------------ 23.4 items
100 % ----------------- x items
65 : 100 = 23.4 : x
65 x = 100 * 23.4
65 x = 2340
x = 2340 : 65
x = 36
Answer: there were 36 items on the test.
Answer:
12 Shirts
9.65 times 12 is 115.8 plus 43 is 158.8
8.40 time 12 is 100.8 plus 58 is 158.8
a. 4 – commutative property
b. 5 – commutative property
c. 0 – identity property
d. 4 – associative property
_____
The commutative property lets you swap the order: (a) + (b) = (b) + (a).
The associative property lets you change the grouping: (a+b)+c = a+(b+c).
The identity property lets you add 0 without changing anything: (a) +0 = (a).
