Equation Form:
x
=
12
,
y
=
50
3
or
x
=
12
,
y
=
50
3
x
=
12
,
y
=
50
3
x
=
12
,
y
=
50
3
x
=
12
,
y
=
50
3
Step-by-step explanation: I have no idea why it looks like that
Step-by-step explanation:
This is a probability related problem.
Probability is the likelihood of an event to occur;
Pr = 
The sample space here is from 1 to 25 which is 25
A.
Pr of a card marked 8; we have just 1 possible outcome;
Pr(8) =
B.
Pr of drawing a card that is a multiple of 5;
Multiples of 5 = 5, 10, 15 and 25
Pr (multiples of 5) =
C.
Pr of drawing a card with odd numbers:
Number of odd numbers between 1 and 25 = 13
Pr(odd numbers) =
D.
Pr of drawing a number with square number on it;
Square numbers between 1 and 25 = 1, 4, 9, 16 and 25
Pr(square numbers) =
= 
So discriminant gives us 3 possibilites connected with result of the equation b^2-4ac. If it is bigger than zero, there are 2 solutions, if answer is exactly 0, then there is one answer and if the number is lower than 0, there are no solutions.
Discriminant of your quadratic equation is (-4)^2-4*1*5=16-20=-4, so there are no solutions.
Mean = (2+4+6+5+2)/5 = 19/5 = 3.8
answer
<span>C. 3.8</span>
Answer:
16
Step-by-step explanation: