I do not know what you mean by in proof but are there multiple choice answers?
Answer:
the vertex is at (2, 8) and the axis of symmetry is x = 2
Step-by-step explanation:
In h(x)=−2x2+8x please use the symbol " ^ " to indicate exponentiation:
h(x)=−2x^2+8x
This is a quadratic equation with coefficients a = -2, b = 8 and c = 0.
The axis of symmetry equation is x = -b/ (2a).
-8
Here, with a = -2 and b = 8, the axis of symmetry is x = --------- = 2
2(-2)
To find the y-coordinate of the vertex, substitute 2 for x in h(x)=−2x^2+8x, obtaining
h(2) = -2(2)^2 + 8(2) = -2(4) + 16 = 8
In summary, the vertex is at (2, 8) and the axis of symmetry is x = 2.
The given term is:
Since here, the numerator i.e.

cannot be factorized.
SO, the only excluded value is found on the basis of the denominator. The denominator should not be equal to 0, otherwise, the fraction will turn out to be zero.
SO, if y

-4, then denominator will not be zero.
Therefore, the excluded value is -4
9514 1404 393
Answer:
when it is a rhombus
Step-by-step explanation:
A kite is a figure in which the diagonals are perpendicular, and one of them is bisected by the other. It will be a parallelogram if both diagonals bisect each other. Such a figure (with mutually perpendicular bisectors as diagonals) is a rhombus.
A parallelogram that is a rhombus will also be a kite.