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3 years ago

What are the distributive property 14k+35

1 answer:

6 0

I’m not too sure of what you are asking. But if you want an equivalent expression, it would be

7(2k+5)

Since 7 is the greatest common factor of both 14 and 35. 14/7=2. 35/7=5

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What is the sign of the product (3)(-3) and (2) (4)

SashulF [63]

Answer:

23 maybe

Step-by-step explanation:

3 0

3 years ago

Evaluate: 2-^4=<br> A.1/16<br> B.1/8<br> c. -8<br> D.-16

SIZIF [17.4K]

Answer:

A. 1/16

Step-by-step explanation:

${2}^{ - 4} = \frac{1}{ {2}^{4} } = \frac{1}{16} \\$

6 0

3 years ago

What type of dilation occurs with a scale factor of 1/4?

Natasha2012 [34]

Answer:

Congruent

Step-by-step explanation:

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3 years ago

Please Help ASAP!! Marking Brainliest!! Divide <img src="https://tex.z-dn.net/?f=12x%5E2%20%2B%204x%5E3%20%2B%2018%20%2B%2016x"

MrMuchimi

Answer:

The answer is C

Step-by-step explanation:

Just calculate it

4 0

3 years ago

Short Response

garik1379 [7]

Answer:

(a)2(89x+84)

(b) $2(89x+84-x^2\pi)$

Step-by-step explanation:

The dimensions of the larger rectangular field are:

Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain = $\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi$

Area of the Field that does not include the soccer field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

$=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)$

8 0

3 years ago