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N76 [4]
3 years ago
10

25 km 7 km 18 km 24 km Find the area!!

Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

75600k^4 m^4 Hope that help !

Step-by-step explanation:

1. Take out the constants (25×7×18×24) kkkkmmmm

2. Simplify 25×7=175 (175×18×24)kkkkmmmm

3. Simplify 175×18=3150 (3150×24)kkkkmmmm

4. 3150×24= 75600kkkkmmmm

5. The answer would be 75600k^4 m^4

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Find the mean and median of this list: 21, 18, 24, 19, 18, 18, 18, 19, 21, 24.
Lena [83]

Answer: mean-20 and median-(19+19)/2 = 19

Step-by-step explanation:

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3 years ago
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Please help me with this one.​
borishaifa [10]

Answer:

  • V = 16
  • W = 48

Step-by-step explanation:

The triangles are congruent when corresponding sides are congruent.

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ΔFGH ≅ ΔABC means corresponding sides are ...

  (GH, BC) = (V, 16)

  (HF, CA) = (48, W)

Corresponding sides being congruent means ...

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5 0
2 years ago
If 15 oranges cost Rs. 70,how much do 39 oranges cost ?​
Minchanka [31]

Answer:

  1. firstly divide 70 by 15 and when the product came multiply it with 39

Step-by-step explanation:

70 ÷ 15 = 4.66

4.66 × 39 = 181.974

7 0
3 years ago
Calculate the allele frequencies in this population of palm trees. A model consisting of a box containing fourteen, randomly arr
bogdanovich [222]

Answer:

The correct answer is

0.5 F, 0.5 f

Step-by-step explanation:

We note the following

Number of colored circles in the box = 14

Number of red circles in the box = 4

Number of purple circles in the box = 6

Number of blue circles in the box = 4

The allele frequency are as follows

Where the frequency is given as

Genotype            Frequency                         Relative frequency        

FF = Red                    4                                       4/14 (0.29≈0.3)                  

Ff = Purple                 6                                       6/14 (0.43≈0.4)

ff = Blue                     4                                       4/14(0.29≈0.3)

Within this population,

We however  have 4 FF = 8 F

                                6 Ff =   6 F + 6 f  and

                                4 ff = 8 f

Total allele = 8+6+6+8 = 28

Relative frequency of F = (8+6)/28 = 14/28 = 0.5

relative frequency of f = (8+6)/28 = 0.5

Therefore the allele frequencies in the palm tree population is

0.5 F, 0.5 f

When in equilibrium we have

However the FF has the product of F×F which is = F² = 0.29 so the frequency of F = √(0.29) = 0.535≈ 0.5

The frequency of Ff is Ff or fF =  0.43 since there is equal number of each allele in Ff we have fF or Ff = Ff = 0.43

Which hives 0.43/2 = F =f ≈ 0.2

To  

and ff = 0.29 so that f = 0.535 ≈ 0.5

Therefore f = F  = 0.5 + 0.2 = 0.7

5 0
3 years ago
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