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ikadub [295]
3 years ago
5

Which statements are true about reflections? Check all that apply.

Mathematics
2 answers:
sukhopar [10]3 years ago
4 0

Answer:

<h3>a. An image created by a reflection will always be congruent to its pre-image </h3>

This statement is true because a reflection is a rigid transformation, that is, it doesn't change the shape and size of the original figure, it just moves it. That's why the reflectio is congruent to its pre-image.

<h3>b. An image and its pre-image are always the same distance from the line of reflection </h3>

This statement is also true, because the line of reflection is an axis that it's a reference for each figure. Also, when we reflect a figure, we are changing some coordinates to their opposite, for example, x=-2 changes to x'=2, which means the distance from the line of reflection is the same, two units.

<h3>c. If a point on the pre-image lies on the line of reflection, the image of that point is the same as the pre-image. </h3>

When we reflect a figure, and its reflected image has a points on the line of reflection, that means the pre-image also has its correspoinding point on the line of reflection, because actually that point won't change its coordinates is ON the line of reflection, that is, when the image reflects, the points remains fixed.

<h3>d. The line of reflection is perpendicular to the line segments connecting corresponding vertices. </h3><h3>f. The line segments connecting corresponding vertices are all parallel to each other</h3>

If we reflect a figure across a vertical axis, the coordinates that change are the horizontal ones.

If we reflect a figure across a horizontal axis, the coordinates that change are the vertical ones.

So, in the first case, if we unit the initial horizontal coordinates with the reflected one, they are gonna be united with horizontal lines, and all of them are gonna be parallels and perpendicular to the line of reflection, which in this case is vertical. That's why d and f are also true.

Gemiola [76]3 years ago
3 0

1,2,3,4,6                                                                                                                                                                   have a good day

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I will give you brainiest if you can answer the questions below.
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Answer:

a. i. 3000 cm² ii. 220 cm  b.  6 feet

Step-by-step explanation:

A. i. The area of the sector AOB is A = ¹/₂r²θ where r = radius of circle = 50 cm and θ = angle subtended at the center of the circle by the sector in radians = 2.4 radians.

So, A = ¹/₂r²θ

= ¹/₂(50 cm)² × 2.4 rad

= ¹/₂ × 2500 cm² × 2.4 rad

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ii. The perimeter of the sector is P = 2r + rθ = (2 + θ)r

substituting r and θ, we have

P = (2 + θ)r

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B. Since length of an arc L = rθ where r = radius = length of pendulum and θ = angle swept by pendulum =  ½ radian and length of the arc swept = 3 feet, the radius is

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8 0
3 years ago
2/3 of the women at the party wear jewelry. 1/4 of the women wear a black dress. If there are 50 more women wearing jewelry than
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To solve this question, let's start by writing down what we know. First of all, let's make a variable, x, which will stand for the number of women at the party (because that's what we want to find). Using this variable, we know:

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1/4x have a black dress

Half the people wearing a black dress also have jewelry, so we know that there is an overlap of 1/4x ÷ 2 = 1/8x between the jewelry and black dress.

To account for this overlap, we can subtract it from both sides. We get

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We know that there are 50 more women with a black dress, so:

13/24x = 1/8x + 50

Simplifying, we get:

13/24x = 3/24x + 50

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That means that there were 120 women at the party.

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