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vitfil [10]
3 years ago
13

PLS HELP ASAP IS THIS TRUE OR FALSE? *image below*

Mathematics
2 answers:
Darya [45]3 years ago
4 0

Answer:

true

Step-by-step explanation:

idek

hodyreva [135]3 years ago
3 0

Answer:

True

Step-by-step explanation:

If we say x-1=0

x=1

F(1)=(1)^3-7(1)^2+15(1)-9

=1-7+15-9

=-6-9+15

=0

So this proves that it's a factor by factor theorem

A factor must give 0 if it's substituted to the equation

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Find cos(2theta) if cos(theta)= 3/4
yuradex [85]
Sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exactly sin(2theta) cos(2theta) tan(2theta) sin(2theta) would it be 2 x (8/17) cos(2theta) would be 2 x (15/17) tan(2theta) would be 2 x (8/17 divided by 15/17) is this correct?
6 0
3 years ago
Please help me right away. There are 2 problems.
koban [17]

For #6;

We know that there are 46% male students and 30% of them are seniors. This means that we have to assume that 30% of the male students are seniors and that 30% of the female students are seniors. Taking 30% of 46% gives us 13.8%.

For #7;

We are looking for the possibility that we choose a junior student (22%) or a sophomore student (28%). This adds up to 50% (22%+28% = 50%). That is out answer.

7 0
3 years ago
Square root of 3x^4 times square root of 5x^2 times square root of 10.
Cloud [144]

Answer:

Step-by-step explanation:

As long as the indices are the same for all the radicals, you can multiply them together. Our index for each of these is 2 (square root) so we multiply them all together and put it under 1 square root sign (radical):

\sqrt{150x^6  The largest perfect square in 150 is 25, and the 6th power on the x needs just to be rewritten in terms of an exponent of 2 to give us:

\sqrt{25*6*(x^3)^2} and pull out the perfect squares to get

5x^3\sqrt{6}

5 0
3 years ago
Read 2 more answers
Find the exact value of the following expression (without using a calculator): tan(Sin^-1 x/2)
Sati [7]

Answer:

tan(Sin^-1 x/2)=  \frac{x/2}{\sqrt{1-x^{2}/4 } }

Step-by-step explanation:

Let sin^-1 x/2= θ

then sinθ= x/2

on the basis of unit circle, we have a triangle with hypotenuse of length 1,   one side of length x/2 and opposite angle of θ.

          tan(Sin^-1 x/2) = tanθ

           tanθ= sinθ/cosθ

as per trigonometric identities cosθ= √(1-sin^2θ)

           tanθ= sinθ/ √(1-sin^2θ)

substituting the value sinθ=x/2 in the above equation

             tanθ= \frac{x/2}{\sqrt{1-x^{2}/4 } }

now substituting the value sin^-1 x/2= θ in above equation

             tan(sin^-1 x/2) =  \frac{x/2}{\sqrt{1-x^{2}/4 } }

!

3 0
3 years ago
1
ki77a [65]
The answer is 12.5 km/hr

45/3.6=12.5
6 0
3 years ago
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