When put in a calculator, the answer is 12.22 (recurring)
Answer:
H. 260
Step-by-step explanation:
We'll begin this problem by first figuring out how many students will be able to sit at the first fourteen tables.
14 tables * 14 students = total students
196 = total students ( for those fourteen tables)
Now we also know that sixteen students can sit on the rest of the cafeteria tables.
We need to find the number of tables can hold sixteen students.
To do this, we'll lead with a simple equation:
18 tables total - 14 tables = # of remaining tables
4 = # of remaining tables
Now we're going to do the same thing we did with the original tables:
4 tables * 16 students = total students
64 = total students
Finally, we add both of the tables max values together:
64 + 196 = 260
Hello,
A(x)=x²-x-72 (m²)
L=(x+8) (cm)= (x+8)/100 (m)
We suppose here x≠-8
(in reality x²-x-72>0 ==>x<-8 or x>9
but x+8>0 ==> x>-8
then
only x>9 are solutions)
W=A(x)/ ((x+8)/100 )=100*(x²-x-72)/(x+8)= 100*(x-9)(x+8)/(x+8)=100*(x-9)
answer ...
to halp you and thank you
Answer:
50%
Step-by-step explanation:
You can literally do it mentally lol
$500,000
- <u>$250,000</u>
$250,000
so by common sense, it's 50%
Hope it helped!
