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ANTONII [103]
2 years ago
12

HELP ASAP I'm putting a lot of points and I'll give you brainiest

Mathematics
1 answer:
Lostsunrise [7]2 years ago
8 0

Answer:

The first coordinate plane has a constant additive rate of change of -1/4

Step-by-step explanation:

Additive rate of change is determined using the slope formula:

m=\frac{y2-y1}{x2-x1}

It must be applied to all of the coordinates given, as sometimes, answer options will have the right slope for the first few options but then change it later in the list. Remember that this is a <em>constant</em> rate of change; it must be the same throughout all of the coordinates.

The first coordinate plane with (-2, 2) and (2, 1) is

m=\frac{1-2}{2-(-2)} =-0.25

so this is the answer. I encourage you to look below to see why the others are <em>not </em>the answer, as there are some tips throughout the rest of my response.

The second plane is a curved line, and this means that it is a function with some kind of exponent or log (judging by the shape, it is probably a quadratic function). Regardless, it will not have a constant change from point to point because of the curve. This is not the answer for those reasons.

The first table is linear (with a constant slope), so that meets the first requirement. The slope, however, is -1/2, so it is not what we are looking for. This is also not the solution.

The last table has a positive slope of 3.3, so this does not fit what we want from an answer.

Hope this helps :)

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dedylja [7]
26 is a part of the whole. the proportion should be set up:

(26/x) = (5/100) It's the overall enrollment that is being asked.

If you also need to solve: Cross multiply, 26(100) = 5x, 2600 = 5x, divide both sides by 5, 520 is the enrollment
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3 years ago
Find the equation of the line. <br><br> GIVING BRAINIEST TO WHOEVER HELPS ME AND GETS IT RIGHT!!!
Anestetic [448]

Answer:

y= -3x + 7

Step-by-step explanation:

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3 years ago
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A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40
malfutka [58]
PART A

The given equation is

h(t) = - 16 {t}^{2} + 40t + 4

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4

We add and subtract

- 16(- \frac{5}{4} )^{2}

to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4

We again factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4

This implies that,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4

The quadratic trinomial above is a perfect square.

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4

This finally simplifies to,

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29

The vertex of this function is

V( \frac{5}{4} ,29)

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

29

PART B

When the ball hits the ground,

h(t) = 0

This implies that,

- 16 ( t- \frac{5}{4}) ^{2} +29 = 0

We add -29 to both sides to get,

- 16 ( t- \frac{5}{4}) ^{2} = - 29

This implies that,

( t- \frac{5}{4}) ^{2} = \frac{29}{16}

t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }

t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}

t = \frac{ 5 + \sqrt{29} }{4} = 2.60

or

t = \frac{ 5 - \sqrt{29} }{4} = - 0.10

Since time cannot be negative, we discard the negative value and pick,

t = 2.60s
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ArbitrLikvidat [17]

Answer: Distributivo

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Solve: y = 9

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