If <span>y = –4x – 7, the x-intercept is found by setting y=0 and solving for x:
</span><span>0 = –4x – 7 => 4x = -7, or x = -7/4 The x-intercept is (-7/4, 0).
</span><span>The y-intercept is found by setting x = 0 and reading off the value of y:
y = –4x – 7 => y = 0 - 7, or y = -7. The y-intercept is (0, -7).</span>
Answer:
see explanation
Step-by-step explanation:
The common difference d of an arithmetic sequence is
d =
-
=
- 
Substitute in values and solve for k, that is
5k - 1 - 2k = 6k + 2 - (5k - 1)
3k - 1 = 6k + 2 - 5k + 1
3k - 1 = k + 3 ( subtract k from both sides )
2k - 1 = 3 ( add 1 to both sides )
2k = 4 ⇒ k = 2
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The n th term of an arithmetic sequence is
=
+ (n - 1)d
= 2k = 2 × 2 = 4 and
d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5
Hence
= 4 + (7 × 5) = 4 + 35 = 39
Two inequalities are equivalent if they have the same set of solutions.
x - 5 ≤ 6 - 5
x - 5 ≤ 1 |add 5 to both sides
x ≤ 6
G(h(0)) = 20
h(x) = x+4
h(0) = 0+4
h(0) = 4
g(x) = 5x
g(h(0)) = g(4) = 5(4) = 20