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omeli [17]
3 years ago
9

May someone please tell me the answer

Mathematics
1 answer:
Pavel [41]3 years ago
6 0
The third one is the correct answer
You might be interested in
Which is bigger square root of 1001 - square root of 1000 or 1/10?
IgorC [24]
Square root of 1001=10.0033
square root of 1000=10
so 10.0033-10=0.0033
1/10=0.1
so, 1/10 is bigger than square root of 1001- square root of 1000
8 0
3 years ago
How to find the area under the standard normal curve between z 1.5 and z 2.5?
alisha [4.7K]
It is possible to calculate mathematically the area under the normal curve between any two values of z.
However, tables/software have been developed to give the areas under the normal curve to the left of particular values of z.  The function is the probability of Z<z, or P(Z<z).
The area between two values z1 and z2 (where z2>z1) is therefore 
P(Z<z2)-P(Z<z1).

For example, to find the area between  z1=1.5, z2=2.5
is 
P(Z<2.5)-P(Z<1.5)
=0.99379-0.93319
=0.06060

(above values obtained by software, such as R)
For example, the value P(Z<2.5) can be calculated using
P(Z<2.5)=erf(2.5/sqrt(2))/2+1/2
where erf(x) is a mathematical function that does not have an explicit formula (calculated by summation of series, or tabulated).
8 0
3 years ago
A rectangular package sent by a postal service can have a maximum combined length and girth (perimeter of a cross sectio) of 108
Morgarella [4.7K]

Answer:

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

Step-by-step explanation:

This is a optimization with restrictions problem.

The restriction is that the perimeter of the square cross section plus the length is equal to 108 inches (as we will maximize the volume, we wil use the maximum of length and cross section perimeter).

This restriction can be expressed as:

4x+L=108

being x: the side of the square of the cross section and L: length of the package.

The volume, that we want to maximize, is:

V=x^2L

If we express L in function of x using the restriction equation, we get:

4x+L=108\\\\L=108-4x

We replace L in the volume formula and we get

V=x^2L=x^2*(108-4x)=-4x^3+108x^2

To maximize the volume we derive and equal to 0

\dfrac{dV}{dx}=-4*3x^2+108*2x=0\\\\\\-12x^2+216x=0\\\\-12x+216=0\\\\12x=216\\\\x=216/12=18

We can replace x to calculate L:

L=108-4x=108-4*18=108-72=36

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

4 0
3 years ago
Read 2 more answers
Five cereal bars are shared equally by 2 students. How many does each student receive?
nata0808 [166]

Answer:

They each get 12.5

5 0
3 years ago
Read 2 more answers
A triangle has side lengths of 5a +3 inches and 2a +3 inches. If the perimeter of the triangle is 3a + 12 inches, which expressi
JulsSmile [24]

Answer:

A. 2a+6

Step-by-step explanation:

I did the test and this is what I got.

7 0
3 years ago
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