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Ber [7]
3 years ago
10

List five common multiples for 8 and 14​

Mathematics
2 answers:
musickatia [10]3 years ago
7 0
Hi :)

The common multiples of 8 and 14 are: 56, 112, 168, 224, 280

They are going in intervals of 56

Hope this helps!
dexar [7]3 years ago
5 0

Answer:

56, 112, 168, 224, and more

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The mean of a set of numbers is 8, and the mode is 9.
ryzh [129]
You can start by looking at the mode of the set of number automatically b and d are eliminated. We then proceed to calculate the mean so add all the numbers in A so it’ll be, 52 then divide by the amount of numbers in the set so 6. 52/6 =8.6
And C ends up being 48 so 48/6 = 8
Therefore your answer is C
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%20%2B%20%20%5Cfrac%7Bx%20-%202%7D%7B3%7D%20%20%3D%20%20%5Cfrac%7Bx%20%2B%203%7D%7B8%7D%20" i
sammy [17]
First multiply each term by 24(the common denominator found by 8×3) to remove the fractions and make things easier.
24(5) + 24( \frac{x - 2}{3} ) = 24( \frac{x + 3}{8} )
This will give you,
120 + 8(x - 2) = 3(x + 3)
Then just continue to simplify and isolate the variable.
120 + 8x - 16 = 3x + 9
8x + 104 = 3x + 9
5x =  - 95
x =  - 19

7 0
3 years ago
Using polynomial identities, multiply the expression (2x+8y)(2x-8y)
igomit [66]
(2x)sqrt 2- 64y2 is the answer
3 0
3 years ago
50 Points. what is the value of x
amm1812

Answer:

X will be = to 6°

Cause the lengths is 6

so 6 ×6° = 36°

I hope am wrong

7 0
2 years ago
Read 2 more answers
A. 12 + 4x = 6x + 10 – 2x
GalinKa [24]

An equation has infinitely many solutions if it can be manipulated all the way to an identity (i.e. an equality where the right and left hand side are the same). We have:

A) 12+4x=6x+10-2x \iff 12+4x=10+4x \iff 12=10

which is impossible

B) 5x+14-4x=23+x-9 \iff x+14 = x+14

which is an equality

C) x+9-0.8x=5.2x+17-8\iff 0.2x+9=5.2x+9 \iff 0.2x=5.2x\iff x=0

which has a unique solution

D) 4x-2x=20 \iff 2x=20 \iff x=10

which has a unique solution

3 0
3 years ago
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