Question 1 of 10
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Answer:
The distance between their eye and the ceiling is 33.06 m.
Explanation:
Given that,
The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center, D = 4.35 mm
Diameter of the eye of pupil, d = 5.1 mm
Wavelength,
We need to find the distance between their eye and the ceiling. Using Rayleigh criteria, we get the distance as follows :
So, the distance between their eye and the ceiling is 33.06 m.