I can't tell what the numbers are on the first one but you got the second one right, and the last one would be different it would be 24 I believe.
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
The answer:
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<X and <Y
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Step-by-step explanation:
Answer:
you are doing -4. so the first parenthesis -4(x+2x+1) is incorrect.
Step-by-step explanation:
Hope this helps plz hit the crown :D
Answer 6
4x -2y +3z^4
4(0) - 2(1) + 3(2)^4
0 - 2 + 24
Answer7
