Answer:(Fog)(-6)=29
Step-by-step explanation:
(fog)=-3(2x+2)-1
=-6x-6-1
=-6x-7
(fog)(-6)= -6(-6)-7
=36-7
=29
Answer:
So, the correct option is A. x = 9, y = 14 , Sides are 11 and 20
Step-by-step explanation:
P.S - the exact question is -
As given in the question ,
Side AB = Side AD
⇒y - 3 = x + 2
⇒y - x = 2 + 3 = 5
⇒y - x = 5 .........(1)
Also, given
Side BC = Side CD
⇒2x + 2 = x + 11
⇒2x - x = 11 - 2
⇒x = 9
∴ equation (1) becomes
y - 9 = 5
⇒y = 5 + 9 = 14
⇒y = 14
∴ we get
x = 9, y = 14
Now,
as given ,
Side AB = y - 3
⇒ AB = 14 - 3 = 11
Side BC = 2x + 2
⇒ BC = 2(9) + 2 = 18 + 2 = 20
Side CD = x + 11
⇒ CD = 9 + 11 = 20
Side DA = x + 2
⇒DA = 9 + 2 = 11
∴ we get
The sides are 11 and 20
So,
The correct option is A. x = 9, y = 14 , Sides are 11 and 20
Use ax^2 + bx + c = 0
ac = -8
b = 2
The factors are 4 and -2.
Plug them into the equation:
x^2 + 4x - 2x - 8
Then factorise it:
x ( x + 4) - 2 (x + 4)
so m = 4
(x + 4)^2
Answer:
6
Step-by-step explanation:
Answer:
128.8 cm²
Step-by-step explanation:
In the image attached below, the regular polygon is a square which is composed of a small square and a large square. In a square, all the sides are equal.
For the small square, half of the diagonal is 4 cm, therefore the length of the diagonal is 8 cm (2 × 4 cm). Let the length of the side be a cm, using Pythagoras theorem:
a² + a² = 8²
2a² = 64
a² = 32
a = √32 = 5.7 cm
The area of the small square = length × length = 5.7 × 5.7 = 32.5 cm²
For the large square, half of the diagonal is 9 cm, therefore the length of the diagonal is 18 cm (2 × 9 cm). Let the length of the side be b cm, using Pythagoras theorem:
b² + b² = 18²
2b² = 324
b² = 162
b = √162 = 12.7 cm
The area of the large square = length × length = 12.7 × 12.7 = 161.3 cm²
The area of the shaded region = Area of large square - Area of small square = 161.3 cm² - 32.5 cm² = 128.8 cm²