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2 years ago

In a school of 4000 students. 40 % of them are boys find the Number of boys and Number of girls

Mathematics

1 answer:

choli [55]2 years ago

3 0

Answer:

1600 boys, 2400 girls

Step-by-step explanation:

4000*4/10=400*4=1600

100-40=60

4000*6/10=400*6=2400

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Please help me answer this question and show work (see attached)

lyudmila [28]

5.6*1 2/5 = 5 3/5 * 1 2/5 =28/5 * 7/5 = 196/25 = 784/100 = 7.84 or 7 21/25

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3 years ago

-(12x-6)=12x 6 solve for x

postnew [5]

6=24x
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3 years ago

Choose a variable to represent one of the unknowns. Express the remaining unknowns in terms of the variable you chose in step 1.

jok3333 [9.3K]

Let's just choose "x" as our variable for the length of a side of the triangle.

Two sides of a triangle are equal in length and double the length of the shortest side.

A triangle has 3 sides. Make the smallest side x then the two equal sides that are double the smallest side are both equal to 2x

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3 years ago

A boat is anchored 2 km south of a lighthouse. The town of Beachton is Located 17 Km East of the lighthouse. What is the distanc

Goryan [66]

Answer: the answer is 27.1 km

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago