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mr Goodwill [35]
3 years ago
14

Which point is the best approximation of the relative maximum of the polynomial function graphed below?

Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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If 5 friends each had one part of a scarf that's 1 and 5/12 yards long what fraction of the scarf could each friend knit
zalisa [80]

Answer:

17/60 yards of scarf

Step-by-step explanation:

If 5 friends each had one part of a scarf that's 1 and 5/12 yards long what fraction of the scarf could each friend knit

To solve the above question:

5 friends = 1 5/12 yards

1 friend = x yards

Cross Multiply

5 × x = 1 × 1 5/12 yards

x = 17/12 yards ÷ 5

x = 17/12 yards × 1/5

x = 17/60 yards of scarf

6 0
4 years ago
​(a) The additive inverse of negative two thirds
LekaFEV [45]
A) The answer to the question is 2/3

b) the answer to the question is 2/3
6 0
4 years ago
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Solve 3(x + 2) > x.​
MaRussiya [10]

Answer:

x > - 3

Step-by-step explanation:

Given

3(x + 2) > x  ← distribute left side

3x + 6 > x ( subtract x from both sides )

2x + 6 > 0 ( subtract 6 from both sides )

2x > - 6 ( divide both sides by 2 )

x > - 3

3 0
4 years ago
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Help?????????????????
lesantik [10]
Y = -4x
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8 0
4 years ago
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In recent years more people have been working past the age of 65. In 2005, 27% of people aged 65–69 worked. A recent report from
Vinil7 [7]

Answer:

a) point estimate is 30%

b) null and alternative hypothesis would be

H_{0}: p=27%

H_{a}: p>27%

c) We reject the null hypothesis, percentage working people aged 65-69 had increased

Step-by-step explanation:

<em>a. </em>

Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals \frac{180}{600}=0.3 ie 30%

<em>b.</em>

Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be

H_{0}: p=27%

H_{a}: p>27%

<em>c.</em>

z-score of the sample proportion assuming null hypothesis is:

\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of working people aged 65–69 (0.3)
  • p is the proportion assumed under null hypothesis. (0.27)
  • N is the sample size (600)

then z=\frac{0.3-0.27}{\sqrt{\frac{0.27*0.73}{600} } } = 1.655

Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.

3 0
3 years ago
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