1 is 52 2 is 30 3 is 30 4 is 62 5 is 118
Answer:
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Step-by-step explanation:
ED = 68
Angle GKH = 31
ABD = 224
Angle AKB = 112
Answer:
The ball traveled 116.25 m when it hit the ground for the fifth term
Step-by-step explanation:
This is a geometric progression exercise and what we are asked to look for is the sum of a GP.
The ball was dropped from a height of 60 m. This means that the initial height of the ball is 60 m.
First value, a = 60
Each time it hit the ground, it bounced up 1/2 (half) of the height that it dropped.
This is the common ratio, r = 1/2 = 0.5
The number of terms it hits the ground is the number of terms in the GP.
number of terms, n = 5
The distance traveled by the ball when it hit the ground for the fifth term will be modeled by the equation:

Answer:
14x + 12
Step-by-step explanation:
8 times x would be 8x
4 times x would be 4x
8x+10+2x+4x+8-6
8x+2x+4x=14x
10+8-6=12
=14x + 12