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3 years ago

8

Three girls (Zeva, Abby and Jenny) went to a hair salon. Each girl had their hair styled (curly, straight, and wavy) and colored

(blonde, red, and black). From the clues below, which chart correctly matches the girl, the hairstyle and the color?

1 answer:

lutik1710 [3]3 years ago

7 0

That doesn’t make sense? Do u mean like guess on what their hair color and style could be

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If the slope is 2 and the line goes through (3,-3) what is the equation?

motikmotik

Answer:

$y = 2x -9$

Step-by-step explanation:

To find the equation of a line using slope and a point, first use the slope to create the basic line using the slope and work from there.

For instance, the base equation here is

$y = 2x$

This line passes through the point (0, 0).

You can then plug in a value for x. In this case, use the value of 3, as it corresponds with your question.

$y = 2 * 3$

A point on the line of y = 2x would thus be (3, 6).

To make the y-value equal -3, you must then subtract from the original equation. There are 9 units between 6 and -3, so you must subtract nine units in the equation. You should get this at the end:

$y = 2x -9$

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3 years ago

Find en equation of the tangent line to the curve

valkas [14]

Y=MX+C C=1 0=m(1)+1 m=-1 Y=-X+1

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4 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

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4 years ago

Help please!!!!! ASAP!!! Only brainliest answer gets points. No wrong answers. Only answer if you know how to do this.

FinnZ [79.3K]

Answer:

The number of pounds of coffee in stock decreased by 9% each hour since the trend began.

There were 40 pounds of coffee in stock when the trend began.

Step-by-step explanation:

p(x)=0.4(.91)^x

= a b^x

where a is the initial value and b = 1-rate of decrease

We know that the number of pounds of coffee will decrease as time goes on.

.4 is the initial value

It is in the hundreds of pound

.4 * 100 = 40 pounds

x is the number of hours

.91 = 1- rate of decrease

Subtract 1 from each side

.91-1 =-rate of decrease

-.09 = -rate of decrease

rate of decrease = .09

rate of decrease = 9 %

That means we keep 91 % of the coffee and sell 9% of the coffee

Lets check the statements:

There were 400 pounds of coffee in stock when the trend began.

False there were 40 pounds when we started

The number of pounds of coffee in stock decreased by 9% each hour since the trend began.

True see above calculations

There were 4000 pounds of coffee in stock when the trend began.

False see above calculations

There were 40 pounds of coffee in stock when the trend began.

True see above calculations

The number of pounds of coffee in stock decreased by 91% each hour since the trend began.

False see above calculations

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3 years ago

If a = 5 in the right triangle what is the value of b and c

Nadya [2.5K]

Answer:

b=5√3, c=10

Step-by-step explanation:

30-60-90 triangle

c=2a

b=a√3

6 0

3 years ago