Answer:
D ≈ 0.925926 g/cm³
Step-by-step explanation:
Density = Mass / Volume
Step 1: Define
M = 25 g
V = (3 cm)³ = 27 cm³
D = ?
Step 2: Substitute and Evaluate for Density
D = 25g / 27 cm³
D = 25/27 g/cm³
D ≈ 0.925926 g/cm³
Given:
In circle F,
units.
To find:
The length of arc EG.
Solution:
It is given that,
units. It means the central angle of arc EG is 122 degrees and the radius of the circle F is 16 units.
Formula for arc length is:

Where, r is the radius and
is the central angle in degrees.
Putting
, we get




Therefore, the length of arc EG is 34.05 units.
Answer:
Step-by-step explanation:
<h3>#1</h3>
- 15 ⋅ 6 - 2² ⋅ 8 + 4³ =
- 15 ⋅ 6 - 4 · 8 + 64 =
- 90 - 32 + 64 =
- 58 + 64 =
- 122
<h3>#2</h3>
- 2³ + 2² ⋅ 2 + 6 - 2¹ ⋅ 2⁰ - 1 =
- 8 + 4 · 2 + 6 - 2 · 1 - 1 =
- 8 + 8 + 6 - 2 - 1 =
- 22 - 2 - 1 =
- 20 - 1 =
- 19
Answer:
Approximately 5 intervals will not capture the true mean hour of sleep freshman get at night.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean implies that there is a (1 - α) probability that the true value of the mean is included in the interval.
Or, the (1 - α)% confidence interval for the mean implies that there is (1 - α)% confidence or certainty that the true mean value is contained in the interval.
And, if 100 such (1 - α)% confidence interval for the mean are computed then 95 of these 100 interval will consist of the true mean value.
In this case it is provided that 100 researchers estimate the population mean hour of sleep freshman get at night, and each one construct a 95% confidence interval for the mean.
Then approximately 95 of these 100 confidence intervals will capture the true mean hour of sleep freshman get at night. And approximately 5 intervals will not capture the true mean hour of sleep freshman get at night.