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Effectus [21]
3 years ago
6

Which of the following is NOT one of the three main ways to control a program when writing code?

Computers and Technology
2 answers:
Karo-lina-s [1.5K]3 years ago
5 0
B. Derivative (Sorry If It’s Wrong)
Klio2033 [76]3 years ago
5 0
The answer would be Derivative. I’ve never heard of derivate programming
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As you are discussing marketing with a client, you try to explain how individuals find sites. Which tool will you explain as the
tigry1 [53]

Answer:

Menus

Explanation:

This is because menus can, and usually do, link to other websites.

8 0
2 years ago
Help plz
Sonbull [250]

1.

first = float(input("First Entry = "))

second = float(input("Second Entry = "))

def func(num1, num2):

   return max(num1, num2)

print(func(first, second))

2.

first = input("First Entry = ")

second = input("Second Entry = ")

def func(word1, word2):

   return sorted([word1,word2])[0]

print(func(first, second))

I hope this helps!

8 0
2 years ago
How does abstraction help us write programs
Misha Larkins [42]

Answer:

Abstraction refines concepts to their core values, stripping away ideas to the fundamentals of the abstract idea. It leaves the common details of an idea. Abstractions make it easier to understand code because it concentrates on core features/actions and not on the small details.

This is only to be used for studying purposes.

Hope it helps!

4 0
3 years ago
Hdhdhrhdh you are not the intended recipient. xmp-qite-xsy.​
Aleks04 [339]

Answer:

ummmm... okay

Explanation:

3 0
2 years ago
Consider a company that needs to sort an array of structures of type Customer by balance, with the largest balance first. Here i
8090 [49]

Answer:

#include <iostream>

#include <string>

#include <cstring>

#include <cstdlib>

using namespace std;

struct Person

{

string name;

int age;

};

int main()

{

struct Person data[10];

struct Person *pData[10],*temp;

string names[] = {"a","b","c","g","z","l","p","q","r","w"};

int num[] = {4,6,34,8,13,90,33,22,18,23};

for(int i=0;i<9;i++)

{

data[i].name = names[i];

data[i].age = num[i];

pData[i] = &data[i];

}

for(int i=0;i<9;i++)

{

for(int j=i+1;j<9;j++)

{

if(pData[i]->name.compare(pData[j]->name)>0)

{

temp = pData[i];

pData[i] = pData[j];

pData[j] = temp;

}

}

}

for(int i=0;i<9;i++)

{

cout<<pData[i]->name<<" "<<pData[i]->age<<endl;

}

}

Explanation:

The line #include <iostream> initializes the program.

This program created an array of only 10 structures, Customer data. Also defined an auxiliary array Customer *pData.

The program uses these parameters to sorts the array of pointers so that when you go through pData in increasing order of index k, the entries pData[k] point to Customer objects in decreasing order by balance, meaning that pdata[0] now points to the customer with the highest balance, and pData[9] points to the customer with the smallest balance.

4 0
2 years ago
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