Answer:
I just did the test and got it right the answer is A. Paul's data has a larger overall spread than Sally's data.
Step-by-step explanation:
Answer:

Step-by-step explanation:
I = prt
Switch sides.
prt = I
We are solving for p. We want p alone on the left side. p is being multiplied by r and t, so we divide both sides by r and t.


Answer:
I = 91.125
Step-by-step explanation:
Given that:
where E is bounded by the cylinder
and the planes x = 0 , y = 9x and z = 0 in the first octant.
The initial activity to carry out is to determine the limits of the region
since curve z = 0 and
∴ 

Thus, z lies between 0 to 
GIven curve x = 0 and y = 9x

As such,x lies between 0 to 
Given curve x = 0 ,
and z = 0,
y = 0 and

∴ y lies between 0 and 9
Then 











I = 91.125
Well, seeing as how she mixed the clay, she has a total of 2 2/8 pounds clay (unsimplified). Although we don't know how many students she has in one class, with simple division of this number we can figure out how many student can finish the project. Removing the 2/8, we can already tell 2 students can do it, so that's a start. Now to divide the 2 pounds into 8ths. Each pound is enough for 8 students, so the 2 pounds totals to 16. Now add the extra 2 students, it's 18 total students. Hope I explained it well enough!
I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer