The equivalent expression is 1.05t and then 24 x 0.05 equals 1.2 so 25.2
Answer:
(a)
Distance from player should be 13.82 feet or 36.2 feet
(b)
The ball will go over the net
Step-by-step explanation:
we are given
The ball follows a path given by the equation

where
x and y are measured in feet and the origin is on the court directly below where the player hits the ball
(a)
net height is 8 ft
so, we can set y=8
and then we can solve for x





we can use quadratic formula




So, distance from player should be 13.82 feet or 36.2 feet
(b)
we can plug x=30 and check whether y=8 ft


we know that
height of net is 8 ft
so, the ball will go over the net
Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
Answer:
4^12 or 16777216
Step-by-step explanation:
4^6* 4^6
We can symplify 4^6* 4^6
Since they both have the same base, we can add there exponent:
4^6* 4^6= 4^12
4^12 equals to 16777216
The equation:
let x represent the unknown number
5+y3=x*05 (or x divided by 2)
y represents the tripled number and x represents the end result. Hope this helps!