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3 years ago

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The following equation has two different solutions. Solve the equation and place one solution in each answer box. The LARGER ans

wer goes in Box1. The SMALLER solution should go in Box2. Solve for x : x 2 + 11 x + 18 = 0

1 answer:

azamat3 years ago

5 0

Answer:

would that be 31 if if im wrong im just nine Step-by-step explanation:

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Caroline knows the height and the required volume of a cone-shaped vase she’s designing. Which formula can she use to determine

timama [110]

Answer:

Option B. $r=\sqrt{\frac{3V}{\pi h}}$

Step-by-step explanation:

we know that

The volume of a cone is equal to

$V=\frac{1}{3}\pi r^{2} h$

Solve for the radius r

That means-----> isolate the variable r

Multiply by 3 both sides

$3V=\pi r^{2} h$

Divide by $(\pi h)$ both sides

$r^{2}=\frac{3V}{\pi h}$

square root both sides

$r=\sqrt{\frac{3V}{\pi h}}$

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4 years ago

PLEASE HELP <br> WILL GIVE BRAINLIEST AND 5.0 STAR RATING

andrezito [222]

Answer:

Fernando walked 4 units

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

What will be the value of

madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

$\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}$

Then you want to know the value of

$\displaystyle\lim_{n\to\infty}a_n$

if it exists.

To show the limit exists and that $a_n$ converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that $a_1=\sqrt{42}\le\sqrt{49}=7$ . Suppose $a_k\le 7$ . Then $a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7$ . So by induction, $a_n$ is bounded above by 7 for all $n$ .

Monontonicity: We have $a_1=\sqrt{42}$ and $a_2=\sqrt{42+\sqrt{42}}$ . It should be quite clear that $a_2>a_1$ . Suppose $a_k>a_{k-1}$ . Then $a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k$ . So by induction, $a_n$ is monotonically increasing.

Then because $a_n$ is bounded above and strictly increasing, the limit exists. Call it $L$ . Now,

$\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}a_{n-1}=L$

$\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}\sqrt{42+a_{n-1}}=\sqrt{42+\lim_{n\to\infty}a_{n-1}}$

$\implies L=\sqrt{42+L}$

Solve for $L$ :

$L^2=42+L\implies L^2-L-42=(L-7)(L+6)=0\implies L=7$

We omit $L=-6$ because our analysis above showed that $L$ must be positive.

So the value of the infinitely nested radical is 7.

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3 years ago

Which equations are related equations to 14 + x = 26?

sertanlavr [38]

Answer: x=26-14

Step-by-step explanation :you need to subtract on both sides so that why it is x=26-14.

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3 years ago

What is the greatest possible error if Irina measured the length of her window as 3.35 feet?

Tatiana [17]

Is it a written response or a multiple chose question?

7 0

4 years ago