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2 years ago

6

The following equation has two different solutions. Solve the equation and place one solution in each answer box. The LARGER ans

wer goes in Box1. The SMALLER solution should go in Box2. Solve for x : x 2 + 11 x + 18 = 0

1 answer:

azamat2 years ago

5 0

Answer:

would that be 31 if if im wrong im just nine Step-by-step explanation:

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I spent a total of $9.25 bowling. I rented bowling shoes for $ 2.50 and bowled 3 games each game cost the same amount create an

JulsSmile [24]

$2.50+3x=$9.25, if you need to work it out, then you do $9.25-$2.50. You take your answer and divide by three... whatever your solution is, equals X. There you go!

4 0

3 years ago

At this weekend’s soccer game, 20 out of the first 50 people who entered the field were not wearing hats. If this sample is repr

Sedbober [7]

Answer:

150 people

Step-by-step explanation:

20/50 = 40%
So 40% are wearing hats and 60% aren't

0.6=60%

250x0.6= 150

6 0

3 years ago

3. How many solutions does the system of equations have? 2x=-10y+ 6 and x+5y=3

ozzi

Answer:

<h2>3. Infinitely many</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}ax+by=c\\dx+ey=f\end{array}\right\\\\(1)\\\text{if}\ a=d,\ b=e,\ c=f,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=5\end{array}\right\\(2)\\\text{if}\ a=d,\ b=e,\ c\neq f,\ \text{then the system of equations has no solution}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=-5\end{array}\right$

$(3)\\\text{if}\ a\neq d\ \text{or}\ b\neq e,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}x-3y=5\\2x-3y=5\end{array}\right$

$\text{We have:}\\\\\left\{\begin{array}{ccc}2x=-10y+6&\text{add 10y to both sides}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}2x+10y=6&\text{divide both sides by 2}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}x+5y=3\\x+5y=3\end{array}\right$

4 0

3 years ago

Write the equation in standard form for the circle with center (0, – 10) and radius 6.

Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: $(x-h)^2+(y-k)^2=r^2$

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

$(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36$

So, equation of circle in standard form with centre (0, – 10) and radius 6. $\mathbf{x^2+(y+10)^2=36}$

5 0

3 years ago

Which transformations can be used to carry ABCD onto itself? Check all that apply<br>PLEASE HELP

eduard

Answer:

A and B

Step-by-step explanation:

Reflection and rotation

3 0

3 years ago

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