3/4 of the lot is 3/4*100=75 yards long. This is 75*3=225 feet.
Using google translate:
When photocopying a credential, it is first enlarged to triple and subsequently the resulting copy is halved. What is the final effect on the original credential? If the credentials is a rectangle of 10 by 6 cm. What area will you have in the first photocopy? And in the second?
Original: 10 by 6 cm ; Area = length * width = 10 x 6 = 60 cm²
first copy: enlarged to triple
10 x 3 = 30
6 x 3 = 18
30 x 18 = 540 cm²
second copy: halved
30 x 1/2 = 15
18 x 1/2 = 9
15 x 9 = 135 cm²
Is that everything for the problem??
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Answer:
A) 5x + 2y = 22
B) -2x + 6y = 3 We'll multiply A) by -3
A) -15x -6y = -66 Then we'll add B)
B) -2x + 6y = 3
-17x = -63
x = 3.7058823529
y = 1.7352941178
Step-by-step explanation:
Answer:
A. a = 10
B. m<FNT = 120°
C. m<KTU = 60°
Step-by-step explanation:
A. (7a + 50)° and (14a - 20)° are corresponding angles. Therefore:
(7a + 50)° = (14a - 20)°
Use this equation to find the value of a
7a + 50 = 14a - 20
Combine like terms
7a - 14a = - 50 - 20
-7a = -70
Divide both sides by -7
-7a/-7 = -70/-7
a = 10
B. m<FNT = (14a - 20)° (alternate interior angles are congruent)
Plug in the value of a
m<FNT = 14(10) - 20
m<FNT = 140 - 20
m<FNT = 120°
C. m<KTU + (14a - 20)° = 180° (linear pair)
Plug in the value of a
m<KTU + 14(10) - 20 = 180
m<KTU + 120 = 180
m<KTU + 120 - 120 = 180 - 120
m<KTU = 60°
