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KiRa [710]
2 years ago
15

Determine the domain and range of the given function.

Mathematics
1 answer:
frez [133]2 years ago
7 0

Answer: domain is all real numbers and range is all real numbers greater than or equal to -2

Step-by-step explanation:

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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
M<2 64 and m<4 =2x-6
-Dominant- [34]

Answer:

5iejksjsjsjsnnsnsnsnsns

6 0
3 years ago
What is the square root of 64y16?<br><br> 4y4<br> 4y8<br> 8y4<br> 8y8
aliya0001 [1]
It is 8y4 becuze 8*2=64 and 4*2=16 and u *2 becuze *2 means square root sorry if I'm wrong :)
7 0
3 years ago
Read 2 more answers
URGENT CASE, need help please, Trigonometric Functions
frez [133]
Dude use the formula of height and distance to find the height of the trangle and then you can find the other side length using Pythagorus theorem
5 0
3 years ago
A grosry storehas adisplay that has 60 oranges and 16 apples. what is the ratio of oranges to apples
ki77a [65]

Answer:

30:16-15:8 That is simplified and I divided it by two.

6 0
2 years ago
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