Answer:
Step-by-step explanation:
B
Answer:
![\large \boxed{\text{5.2 lb$\cdot$in}^{-2}}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B5.2%20lb%24%5Ccdot%24in%7D%5E%7B-2%7D%7D%7D)
Step-by-step explanation:
In a direct proportion,
Pressure = constant × temperature
p = kT
We can use the initial conditions to find the value of k, and then calculate the pressure at the new temperature.
1. Determine the value of k
Data:
p₁ = 6 lb·in⁻²
T₁ = 440 K
Calculation:
![\begin{array}{rcl}p_{1} & = &k \times T_{1}\\6 & = &k \times 440\\k & = & \dfrac{6}{440}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7Dp_%7B1%7D%20%26%20%3D%20%26k%20%5Ctimes%20T_%7B1%7D%5C%5C6%20%26%20%3D%20%26k%20%5Ctimes%20440%5C%5Ck%20%26%20%3D%20%26%20%5Cdfrac%7B6%7D%7B440%7D%5Cend%7Barray%7D)
2.Calculate the new pressure
![\begin{array}{rcl}p_{2} & = &k \times T_{2}\\& = &\dfrac{6}{440} \times 380\\\\& = & \mathbf{5.2}\end{array}\\\text{The new pressure is $\large \boxed{\textbf{5.2 lb$\cdot$in}^{\mathbf{-2}}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7Dp_%7B2%7D%20%26%20%3D%20%26k%20%5Ctimes%20T_%7B2%7D%5C%5C%26%20%3D%20%26%5Cdfrac%7B6%7D%7B440%7D%20%5Ctimes%20380%5C%5C%5C%5C%26%20%3D%20%26%20%5Cmathbf%7B5.2%7D%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20new%20pressure%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B5.2%20lb%24%5Ccdot%24in%7D%5E%7B%5Cmathbf%7B-2%7D%7D%7D%24%7D)
The sum is 41.22 because first you turn all of the fractions into decimals and then it’s easier to add them all together all at once.
Answer is 2 1/2
Step by Step explanation