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3 years ago

WILL MARK BRAINLIST

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

Answer:

If the solutions (or roots, or zeros) are -4 and -8 then the factors are (x+4) and (x-8), so the equation would by:

Y=(x+4)(x-8) foil it out.

Y=x(2)+4x-(8)x-6)

Y=x(2)+(5/2)x-6

Hope this helped.

Aleks [24]3 years ago

6 0

Answer:

The quadratic equation is x^2 + 4x - 32 = 0

Step-by-step explanation:

(x - 4)(x+8) = 0

x^2 + 4x - 32= 0

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Answer:

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Step-by-step explanation:

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3 years ago

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The weights of 83 randomly selected windshields were found to have a variance of 1.88. Construct the 95% confidence interval for

Morgarella [4.7K]

Answer:

95% confidence interval for the population variance = (1.42 , 2.62).

Step-by-step explanation:

We are given that the weights of 83 randomly selected windshields were found to have a variance of 1.88.

So, firstly the pivotal quantity for 95% confidence interval for the population variance is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, $s^{2}$ = sample variance = 1.88

$\sigma^{2}$ = population variance

n = sample of windshields = 83

So, 95% confidence interval for population variance, $\sigma^{2}$ is;

P(58.85 < $\chi^{2} __8_2$ < 108.9) = 0.95 {As the table of $\chi^{2}$ at 82 degree of freedom

gives critical values of 58.85 & 108.9}

P(58.85 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 108.9) = 0.95

P( $\frac{ 58.85}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{108.9}{(n-1)s^{2} }$ ) = 0.95

P( $\frac{ (n-1)s^{2}}{108.9 }$ < $\sigma^{2}$ < $\frac{ (n-1)s^{2}}{58.85 }$ ) = 0.95

95% confidence interval for $\sigma^{2}$ = ( $\frac{ (n-1)s^{2}}{108.9 }$ , $\frac{ (n-1)s^{2}}{58.85 }$ )

= ( $\frac{ (83-1)\times 1.88}{108.9 }$ , $\frac{ (83-1)\times 1.88}{58.85 }$ )

= (1.42 , 2.62)

Therefore, 95% confidence interval for the population variance of the weights of all windshields in this factory is (1.42 , 2.62).

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Graph the line with slope -2/5 and y-intercept -3

aksik [14]

Answer:

emmm we cant graph

Step-by-step explanation:

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3 years ago

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Anvisha [2.4K]

Answer:

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Step-by-step explanation:

As the experiment is based on the difference between the results of a pair, the most appropiate test is a paired t-test.

If the 80 people group had been dividided in 2 and then compare the means for each group, it would have been a independent samples t-test.

For each pair, a variable d (for difference) is calculated and used as the outcome sample to perform the test.

Then, the null hypothesis will state that the population mean for this difference is not significantly different from 0, and the alternative hypothesis claiming it is signficant different from 0.

The sample means for the treatment group and the placebo is not individually calculated, as only the difference for each pair is used as sample in a paired t-test.

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