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2 years ago

Using the quadratic formula, which of the following are the zeros of the

Mathematics

1 answer:

Nana76 [90]2 years ago

8 0

Answer:

y=x2-X-5 is zero of quadratic equation

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Click on the picture thanks so much

-BARSIC- [3]

Answer:

$3.06

Step-by-step explanation:

First we need to calculate the mark up

The mark-up rate is 150% = 1.5 as a decimal

New price = original price + original price * markup rate

= 61.20 + 61.20* 1.50

= 61.20 + 91.80

= 153

The new price is 153.00

Commission is the price times his commission rate

commission = price* .02

= 153*.02

= 3.06

Neil will make 3.06 on the sale of the table

7 0

3 years ago

Is my answer correct? If its not, would you mine telling me what is correct?

Luden [163]

Answer:

Sorry but you have the y and x mixed up

Step-by-step explanation:

You have them mixed up

6 0

2 years ago

Read 2 more answers

A scuba diving company currently charges $100per dive. On average, there are 30 customers per day. The company performed a study

Semenov [28]

A. Total Revenue (R) is equal to price per dive (P) multiplied by number of customers (C). We can write $R=PC$ .

Per price increase is $20. So four price increase is $ $20*4=$80$ . Hence, price per dive is 100+80=$180.

Also per price increase, 2 customers are reduced from 30. For 4 price increases, $4*2=8$ customers are reduced. Hence, total customers is $30-8=22$ .

So Total Revenue is:

$R=180*22=3960$

B. Each price increase is 20. So x price increase is 20x. Hence, new price per dive would be equal to the sum of 100 and 20x.

Also per price increase, customers decrease by 2. So per x price increases, the customer decrease is 2x. Hence, new number of customers is the difference of 30 and 2x.

Therefor we can write the quadratic equation for total revenue as the new price times the new number of customers.

$R=(100+2x)(30-2x)=-40x^{2}+400x+3000$

C. We are looking for the point (x) at which the equation modeled in part (B) gives a maximum value of revenue (y). That x value is given as $x=-\frac{b}{2a}$ , where a is the coefficient of $x^{2}$ and b is the coefficient of x. So we have,

$x=-\frac{b}{2a}=- \frac{400}{(2)(-40)}=5$

That means, the greatest revenue is achieved after 5 price increases. Each price increase was 20, so 5 price increase would be $5*20=100$ . So the price that gives the greatest revenue is $100+100=200$ .