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Snezhnost [94]
3 years ago
5

At this point I’m just gonna post all the questions so stay online. y’all are so smart. 2 more to go! Xoxo <3

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer:172.5

Step-by-step explanation:Xoxo

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miv72 [106K]

Answer:

The value of x is 7.

Step-by-step explanation:

First, you have to make the left side into 1 fraction by making the denormintor the same and make it into simplest form :

\frac{x}{3}  +  \frac{x}{6}

=  \frac{x \times 2}{3 \times 2}  +  \frac{x}{6}

=  \frac{2x}{6}  +  \frac{x}{6}

=  \frac{2x + x}{6}

=  \frac{3x}{6}

=  \frac{x}{2}

Next you have to multiply both sides by 2 in order to make x the subject :

\frac{x}{2}  =  \frac{7}{2}

\frac{x}{2}  \times 2 =  \frac{7}{2}  \times 2

x = 7

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3 years ago
How to rewrite 4 x parentheses 25 + 4 parentheses
MissTica
4×29 because 25+4 is 29, we did the thing inside the parentheses so the parentheses is now gone, becoming 4×29
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3 years ago
Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a
Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the  we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = 5*sin(\frac{2*\pi*t}{15} )+6

When Jamie is 9 meters above the ground and rising we have

9 = 5*sin(\frac{2*\pi*t}{15} )+6 or 3/5 = sin(\frac{2*\pi*t}{15} ) = 0.6

which gives sin⁻¹(0.6) = 0.643 =\frac{2*\pi*t}{15}

from where t = 1.536 s

Therefore Jamie is gaining altitude at

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = 1.676 m/s.

(b) Jamie is rising most rapidly when   the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15}) =0, π, 2π

Therefore -sin(\frac{2\pi t}{15} ) = 0 whereby t = 0 or

\frac{2\pi t}{15} = π and t =  7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) = - 2/3π m/s which is decreasing

so we try at t = 15 s and we have \frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pim/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

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Answer:

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Step-by-step explanation:

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