Answer: The answer is 139 feet
H = height of the pole =?
BC = ED = height of the transit = 4 ft
CD = BE = distance moved away from the base of the pole = 140 ft
Consider the ΔABE
tan44 = AE/BE
tan44 = h/140
h = 140 tan44
h = 135.2 ft
H = height of pole = AE + ED = h + ED = 135.2 + 4
H = 139.2 ft
Step-by-step explanation:
F(x)= 9x^3 + 2x^2 - 5x + 4
g(x)= 5x^3 - 7x + 4
f(x) - g(x)
9x³ + 2x² - 5x + 4 - (5x³ - 7x + 4)
9x³ + 2x² - 5x + 4 - 5x³ +7x - 4
9x³ - 5x³ + 2x² -5x + 7x + 4 - 4
4x³ + 2x² + 2x
If QR is a median, then:

We have NO = 30, MP = 9x - 42 and QR = x + 15. Substitute:

<h3>Answer: A. 6</h3>
X + 3 = 0
2x - 1 = 0
It would be D.