With the information of f(2) = 22-5, you can assume the equation will be f(x) = 11x-5. Using this, you can calculate f(5) by doing 11(5)-5, which is 50. 22-5 is 17, so 50+17=67
You can get a vertical asymptote at x=1 using y = 1/(x-1) You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1 You can move the horizontal asymptote up to y=2 by adding 2
