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UkoKoshka [18]
3 years ago
14

the uniform distribution over the interval 8.5 to 11.5 gallons per minute. Find the probability that between 9.0 gallons and 10.

0 gallons are pumped during a randomly selected minute.
Mathematics
1 answer:
Tema [17]3 years ago
3 0

Answer: 1/3

Step-by-step explanation:

Here is the complete question:

machine is set to pump cleanser into a process at the rate of 9 gallons per minute. Upon inspection, it is learned that the machine actually pumps cleanser at a rate described by the uniform distribution over the interval 8.5 to 11.5 gallons per minute. Find the probability that between 9.0 gallons and 10.0 gallons are pumped during a randomly selected minute.

The Probability of the above question will be calculated as:

= (10-9) / (11.5 - 8.5)

= 1/3

The above is the easier way to solve this

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56.8

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What values of c and d make the equation true? Assume x>0 and 20.
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c=1 and c=3

Step-by-step explanation:

If x>0 and y>0, then

\sqrt{\dfrac{50x^6y^3}{9x^8}}=\sqrt{\dfrac{25\cdot 2y^2\cdot y}{9x^2}}=\dfrac{5y\sqrt{2y}}{3x}.

9x

8

50x

6

y

3

=

9x

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25⋅2y

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If

\dfrac{5y\sqrt{2y}}{3x}

3x

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is equal to

\dfrac{5y^c\sqrt{2y}}{dx},

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then

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y=y

c

⇒c=1,

3x=dx⇒d=3.

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2 years ago
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