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Anna71 [15]
3 years ago
8

Someone find x !!!!!!

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0
14. 128
15.25
16.90
those should be right
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Pleeeeeassseee heelp meeeeeeeeeeeeeeeeeeee
Alisiya [41]

Answer:

\boxed{Length \: of \: each \: side \: of \: cube = 5.2 \: mm}

Given:

Volume of cube = 140.608 cubic millimetres

Step-by-step explanation:

Let the length of each side of cube = a

=  > Volume \:  of  \: cube =  {a}^{3}  \\  \\  =  > 140.608 =  {a}^{3}  \\  \\  =  >  {a}^{3}  = 140.608 \\  \\  =  >  {a}^{ \cancel{3}}  =  {5.2}^{ \cancel{3}}  \\  \\  =  > a = 5.2

Therefore length of each side of cube = 5.2 mm

4 0
4 years ago
Can someone please help me with math
Anastasy [175]

Answer:

100 gallon for every 50 mile

Step-by-step explanation:

if you look at it the 50 meet up with 100 and 50 says it's mile and 100 is gallon so you got 100 gallon for every 50 mile

5 0
3 years ago
In one school year, the students spent a total of 840 hours in their classes. If they have EIGHT different classes, how many hou
ziro4ka [17]

Answer:

280 hours

Step-by-step explanation:

8 0
3 years ago
The concentration of hexane (a common solvent) was measured in units of micrograms per liter for a simple random sample of sixte
goldenfox [79]

Answer:

Yes, it can be concluded that the mean hexane concentration is less in treated water than in unsaturated water

Step-by-step explanation:

The number of of specimen in the samples of untreated water, n₁ = 16

The sample mean, \overline x_1 = 228.0

The sample standard deviation, s₁ = 4.3

The number of of specimen in the samples of treated water, n₂ = 20

The sample mean, \overline x_2 = 224.6

The sample standard deviation, s₂ = 5.0

The level of significance = 0.10

The null hypothesis, H₀; \overline x_1 ≥ \overline x_2

The alternative hypothesis, Hₐ;  \overline x_1 < \overline x_2

The degrees of freedom = 16 - 1 = 15

The test statistic, t_{\alpha} = 1.341

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}

Plugging in the values, we get;

t=\dfrac{(224.6- 228.0)}{\sqrt{\dfrac{5.0^{2}}{20} -\dfrac{4.3^{2} }{16}}} \approx -11.0675

Given that the t-value is large, the corresponding p-value is low, therefore, we fail to reject the null hypothesis and there is considerable statistical evidence to suggest that the mean hexane concentration is less in treated than in untreated water, therefore, we have; \overline x_1 ≥ \overline x_2

6 0
3 years ago
An arch has the equation y=-2/81x^2+18. Find it’s maximum height
Andrew [12]

Answer:

at y = 18 units

Step-by-step explanation:

An arch has the equation y=-2/81x^2+18. Find it’s maximum height

This is a parabolic function

Maximum at the vertex

x = -0/(2*(2/81)) = 0

max  at  y = 18 units

6 0
3 years ago
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