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lora16 [44]
3 years ago
10

True or false a rectangle with four right angles is a square

Mathematics
2 answers:
iragen [17]3 years ago
8 0
False a rectangle could never be a square
bagirrra123 [75]3 years ago
7 0

Answer:

False.

Step-by-step explanation:

Every rectangle had 4 right angles, including squares, which are also rectangles! ^^ Squares are basically just special rectangles!

You might be interested in
If you multiply 0.86 by 7.36, how many decimal places will be in the product?
AURORKA [14]

Answer:

4

Step-by-step explanation:

There are 4 numbers to the right of decimals in question.

Pls mark Brainiest :)

6 0
3 years ago
Read 2 more answers
Is 237.5 less than or greater than 2 8/24
Schach [20]

Alright!

In order to properly compare these numbers, they need to look the same!

Lets change 2 8/24 into a <em>decimal.</em>

To do this, we need to convert it into an <u>improper fraction </u>

Follow these steps:

2 \frac{8}{24} \\

We multiply the<em> whole number</em> (2) by the <em>denominator </em>(24) and then add the <em>numerator </em>(8). The improper fraction will keep the same <em>denominator </em>(24) at the end.

2 × 24 = 48

48 + 8 = 56

\frac{56}{24}

Now, lets use a calculator to see what 56/24 is!

56 ÷ 24 = 2.33

237.5 is GREATER than 2 \frac{8}{24} \\

Hope I helped! Comment if you have questions :)

7 0
4 years ago
For the function defined by f(t)=2-t, 0≤t&lt;1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

5 0
4 years ago
Ethan buys a video game on sale. If the video game usually costs $39.99, and it was on sale for 20% off, how much did Ethan pay?
Ann [662]
Hello There!

Ethan would pay $31.99  or rounded up two 32 which ever is your answer choice 

Thus being why.

if you times 39.99 x .20 you get 7.998

39.99 - 7.998 is 31.99

Hope This Helps!
7 0
4 years ago
Read 2 more answers
HELP I NEED HELP ASAP
levacccp [35]

Answer:

I think it's A

Step-by-step explanation:

the line is going up and the more it goes up it looks like it will be 2.5

7 0
3 years ago
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