Ask question

Ask question

All categories

Juliette [100K]

2 years ago

5

Ruby’s homework covers multiplication with the powers of 10 the first question on her homework is 82.6 x 10 to the power of 2 wh

at is the value of expression?

1 answer:

Elina [12.6K]2 years ago

7 0

Answer:

826

Step-by-step explanation:

82.6 x 10 to the power of 2 :

8.26 * 10^2

8.26 * (10 * 10)

8.26 * (100)

= 826

You might be interested in

Minchanka [31]

Answer:

D.4.7%

Step-by-step explanation:

5 0

3 years ago

Please hellp me mmmmmmmmeeeeeeeeeee

luda_lava [24]

0.2 if 1 Mile is 5 Minutes then every 0.1 mile is 30 seconds so 1 minute would be 0.2

3 0

2 years ago

HELP NEEDED , YOU WILL GET 10 POINTS !

Nitella [24]

Answer:

stop cheating on your schoology test;)

Step-by-step explanation:

8 0

2 years ago

Andrew wants to place grouping symbols in the expression

Ipatiy [6.2K]

C.

15 + (25 – 18) ÷ 2

sorry if i'm wrong!

8 0

3 years ago

Read 2 more answers

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

3 years ago