Answer:
x>3
Step-by-step explanation:
<span>The vertex of the parabola is the highest or lowest point of the graph.
</span><span>y=-4x^2+8x-12 = -4 (x^2 -2x +3)
Lets work with this now: </span>x^2 -2x +3
x^2 -2x +3 -> what is the closeset perfect square?
x^2 -2x +1 = (x-1)^2
So
x^2 -2x +3 = (x-1)^2 +2
Replacing to original
y=-4x^2+8x-12 = -4 (x^2 -2x +3) = -4 ((x-1)^2 +2) = -4 (x-1)^2 - 8
The min or max point is where the squared part = 0
So when x=1 , y= -4*0-8=-8
This will be the max of the parabola as there is - for the highest factor (-4x^2)
The max: x=1, y= -8
Answer:

Explanation:
The figure is not a regular hexagon. It is an irregular hexagon.
Please, find attached the picture with the original question and the figure.
You can split the figure into two triangles and one rectangle.
The rectangle has dimensions: 7units × 4units, thus its area is 28 units².
Both the upper triangle and lower triangle have base 7 units and height 2 units.
Hence the area of each triangle is:

Hence, the area of the hexagon is:
