Answer:
d = 576
Step-by-step explanation
Think of the two different speeds as belonging to 2 different cars going to the same place, taking the same route and going to the same place.
Let the time traveled by the fast car = t
Let the time traveled by the slower car = t+4
Let the rate of travel of the slow car = 36 mph
Let the rate of travel of the fast car = 48 mph
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d = 36*(t + 4)
d = 48 * t
Since the distance is the same, they can be equated.
48t = 36(t + 4) Remove the brackets.
48t = 36t + 144 Subtract 36t from both sides.
48t - 36t = 144 Combine
12t = 144 Divide by 12
t = 144/12
t = 12
Therefore the faster car takes 12 hours to get where it is going.
d = 48 * t
d = 48 * 12
d = 576
Answer:
Step-by-step explanation:
(x²-6x-3)(7x²-4x+7)= ?
Multiply each term of 2nd bracket with the 1st bracket:
=7x²(x²-6x-3) -4x(x²-6x-3) +7(x²-6x-3)
=7x^4-42x^3-21x^2-4x^3+24x^2+12x+7x^2-42x-21
Now solve the like terms:
=7x^4-46x^3+10x^2-30x-21
Therefore the answer is (x²-6x-3)(7x²-4x+7)=7x^4-46x^3+10x^2-30x-21 ....
Answer:
Actual height of church = 512 feet
Step-by-step explanation:
Given:
Scale model;
1 inch = 256 feet
Height of church (Scale model) = 2 inches
Find:
Actual height of church
Computation:
Actual height of church = Height of church (Scale model) x scale length
Actual height of church = 2 inches x 256 feet/inches
Actual height of church = 2 x 256 feet
Actual height of church = 512 feet
Answer: 5 the gcf is 5
Step-by-step explanation:
Answer:
I think it might be data and range
Step-by-step explanation:
the answer is at the top
