. For a daily airline flight between two cities, the number of pieces of checked luggage has a mean of 380 and a standard deviat
2 answers:
Answer: We have 95% chances of flight that would be expected from 340 to 420 pieces of checked luggage.
Step-by-step explanation:
Since we have given that
The number of pieces of checked has mean and standard deviation as follows:
Sample mean ( ) = 380
Sample standard deviation ( )= 20
We need to find the percentage of flights would be expected from 340 to 420 pieces of checked luggage.
So, if we take X = 340,
As it is normal distribution,
Then,
Similarly, if we take X = 420 pieces,
so, there are 2 standard deviations above the mean and 2 standard deviations below the mean.
So, in this case, we have 95% chances of flight that would be expected from 340 to 420 pieces of checked luggage.
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Since they are both shaded below, the intersection of the shaded regions, is the region colored in blue.
Both lines are included, since they are solid lines.
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, thus, the equation is:
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thus the equation of the second line is :
We have to decide on the direction of the inequality sign, so we pick a point, for example (0, 4) which is not in the colored regions of the lines,
so we write the inequalities so that they do not hold for (0, 4)
line 1:
y≥x+4
4≥0+4=4 is true, so we change the sign and write : y≤x+4
similarly, line 2:
y≤-2x+3
4≤-2*0+3=3, which is not true, so we have the correct direction.
Note that since the lines were solid, we include the equality case:
Answer:
the shaded region is the solution to the system of inequalities:
i) y≤x+4
ii) y≤-2x+3
The second line, through (1, 1) and (2, -1) is the purple line.
Since they are both shaded below, the intersection of the shaded regions, is the region colored in blue.
Both lines are included, since they are solid lines.
The equation of the first line can be found as follows:
the slope is
The equation of the second line can be found as follows:
the slope is
thus the equation of the second line is :
We have to decide on the direction of the inequality sign, so we pick a point, for example (0, 4) which is not in the colored regions of the lines,
so we write the inequalities so that they do not hold for (0, 4)
line 1:
y≥x+4
4≥0+4=4 is true, so we change the sign and write : y≤x+4
similarly, line 2:
y≤-2x+3
4≤-2*0+3=3, which is not true, so we have the correct direction.
Note that since the lines were solid, we include the equality case:
Answer:
the shaded region is the solution to the system of inequalities:
i) y≤x+4
ii) y≤-2x+3