Answer:
(x - 4)(x^2 + 7)
Step-by-step explanation:
x^2 is a factor of the first two terms: x^3 - 4x^2 = x^2(x - 4).
7 is a factor of the last two terms: 7(x - 4).
Note how (x - 4) is a factor of the entire four-term expression given above.
Then: x^3-4x^2+7x-28 = (x - 4)(x^2 + 7)
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
