The answer is <span>Anaphase I separates homologous chromosomes and anaphase II separates sister chromatids into daughter cells.</span>
Meiosis is a cell division which results in the reduction of chromosome number by half - from diploid to haploid - in daughter cells. It consists of meiosis I and meiosis II. Meiosis I produces two haploid cells. Meiosis II is analogous to mitosis, so in total, meiosis results in four haploid cells. So, in meiosis, there are two anaphases - the anaphase I in meiosis I and the anaphase II in meiosis II.
<span>In anaphase I, the sister chromatids separate from each other to the opposite sides of the cells. In meiosis I there are 46 chromosomes in duplicate, which are present as pairs of sister chromatids. In anaphase of meiosis II, since the cell is haploid, there are 23 chromosomes in duplicate, which are present as sister chromatids.</span>
Answer:
There are four possible combinations of gametes for the AaBb parent. Half of the gametes get a dominant A and a dominant B allele; the other half of the gametes get a recessive a and a recessive b allele. Both parents produce 25% each of AB, Ab, aB, and ab.
Explanation:
2 is crescent and 4 is gibbous
When two react with two fatty acid molecules a digylceride forms. And when three react with three fatty acid molecules a triglyceride forms. Triglycerides formed <span>between glycerol and unsaturated fatty acids are usually oils. Those </span>formed<span> with saturated acids are usually fats.</span><span />
