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ddd [48]
3 years ago
10

The explains why a x b = b x a and a + b = b + a.

Mathematics
1 answer:
Sliva [168]3 years ago
6 0
Answer: The commutative property

Explanation: the commutative property of addition/multiplication states that no matter what order the expression is in it will equal the same thing.
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Fully simplify.<br> (5x^5-y)^2
Aleksandr-060686 [28]

Answer:

I think that's right been a while

Step-by-step explanation:

25x^5-y^2

5 0
2 years ago
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I’m doing the Order of operations and I’m asking what 6 x (8-3) - 5^2
Ymorist [56]

Answer:

The answer is 5

4 0
3 years ago
What is bigger 5/6 or 11/12?
Maurinko [17]
First you find the common deoninator.
Step 1: Reduce (simplify) entered fractions to lowest terms, if the case:Fraction: 5 / 6 it's already reduced to lowest terms
Fraction: 11 / 12 it's already reduced to lowest terms
Step 2: Calculate LCM (lowest common multiple) of the reduced fractions' denominators, it will be the common denominator of the compared fractions:Denominator 6, factored = 2 * 3
Denominator 12, factored = 22<span> * 3</span>
LCM (6, 12) = 22<span> * 3 = 12</span>Step 3: Calculate each fraction's expanding number (LCM divided by each fraction's denominator):For fraction: 5 / 6 is 12 : 6 = (22<span> * 3) : 6 = 2</span>
For fraction: 11 / 12 is 12 : 12 = (22<span> * 3) : 12 = 1</span>
Step 4: Expand fractions to bring them to the common denominator (LCM):5 / 6 = (2 * 5) / (2 * 6) = 10 / 12
<span>11 / 12 = (1 * 11) / (1 * 12) = 11 / 12</span>
4 0
3 years ago
0.5 recurring as a fraction​
Klio2033 [76]

0.5 = 5/10 = 1/2

The answer is 1/2

5 0
2 years ago
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Part A - Construct a circle of any radius, and draw a chord on it. The construct the radius of the circle that bisects the chord
Julli [10]

Answer:

It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.

Step-by-step explanation:

i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.

ii. Construct the radius to bisect the chord, dividing it into two equal parts.

Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.

The construction to the question is herewith attached to this answer for more clarifications.

5 0
3 years ago
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