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3 years ago

(-327) + 420 + 521=

Mathematics

2 answers:

Vikentia [17]3 years ago

7 0

I got 614 but I may be wrong

Tems11 [23]3 years ago

6 0

144 hope this helps! :)

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I need help with this does anyone understand this?

soldier1979 [14.2K]

Answer:

Let y = f(x)

$= > y = \frac{19}{ {x}^{3} }$

$= > {x}^{3} = \frac{19}{y}$

$= > x = \sqrt[ 3]{ \frac{19}{y} }$

${f}^{ - 1} (x) = \frac{ \sqrt[3]{19} }{ \sqrt[3]{x} }$

<h2>option A</h2>

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3 years ago

A right cylinder has a radius of 5 and a height of 9. What is its surface area?

harkovskaia [24]

Answer:

B. 140π units²

Step-by-step explanation:

Surface area of a cylinder:

2πrh + 2πr²

2π(5)(9) + 2π(5²)

90π + 50π

140π

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2 years ago

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

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3 years ago

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KiRa [710]

Answer:

Step-by-step explanation:

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3 years ago

Toy-rific Toy Store received a shipment of glow-in-the-dark bracelets.

MaRussiya [10]

Answer: 12

Step-by-step explanation:

106.80/8.90 =12

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2 years ago