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bixtya [17]
3 years ago
14

List two things that happen when invisible waves of radiant energy come into contact 'with a solid.

Physics
2 answers:
Contact [7]3 years ago
8 0

Answer: they vibrate faster and becomes hotter

Explanation:

.

True [87]3 years ago
6 0
When invisible waves of radiant energy come into contact with a solid, the particles in the solid vibrate faster. The solid becomes hotter. The solid can in turn, reradiate some of this energy back into the area where it is standing.
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Snorkelers breathe through tubes that extend above the surface of the water. In prin- ciple, a snorkeler could go deeper with a
Yanka [14]

Answer:

h = 1.02 m

Explanation:

This is a fluid mechanics exercise, where the pressure is given by

       P = P_{atm} + ρ g h

The gauge pressure is

      P - P_{atm}  = ρ g h

In this case the upper part of the tube we have the atmospheric pressure. and the diver can exert a pressure 10 KPa below the outside pressure, this must be the gauge pressure

     P_{m} =    P - P_{atm}

     P_{m} = ρ g h

     h =P_{m} / ρ g

calculate

     h = 10 103 / (1000 9.8)

     h = 1.02 m

This is the depth at which man can breathe

8 0
3 years ago
Please I really need help on these
blagie [28]

Answer:

  3, 4, 2

Explanation:

I can't see the final ones.

4 0
3 years ago
A soccer player kicks a ball horizontally at 28 m/s from a bridge and hits the ground after 1.5 s. What is the range of the ball
Lelu [443]

Answer:

42

Explanation:

range of ball = u×t

= 28×1.5

=42

8 0
2 years ago
What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high? (Formula: PE = mgh)
Lisa [10]

Answer:

The answer would be 735J

Explanation:

PE=mgh

=(mass)(force of gravity)(height)

=(25kg)(9.8m/s^2)(3m)

=735J

8 0
3 years ago
Read 2 more answers
A race car starting from rest accelerates uniformly at a rate of 3.90 m/s^2 what is the cars speed after it has traveled 200 m.
snow_tiger [21]
The formula for accelerational displacement is at^2/2, so we know that 3.9t^2/2 = 200, or 3.9t^2 = 400. t = \sqrt{400/3.9} \approx 10.12739367, at = v, so 3.9 * 10.12739367 \approx 39.5  m/s
6 0
3 years ago
Read 2 more answers
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